Selectable contour(f) divisions

Community matplotlib-users
#1

In using the contour as in:

contour(X,Y,Z,N)

N is a number of automatically chosen levels.

I would like to contour based on data divisions.

For instance, perhaps I'd like to use a contour or color-fill
(contourf) every 2 units. I'm not seeing how to accomplish this. Any
points in the right direction would be appreciated.

Thanks!

Bruce

···

---------------------------------------
Bruce W. Ford
Clear Science, Inc.
bruce@...2905...
http://www.ClearScienceInc.com
8241 Parkridge Circle N.
Jacksonville, FL 32211
Skype: bruce.w.ford
Google Talk: fordbw@...287...

#2

Hi Bruce,

why don't you use contour as in the following :wink:

contour(X,Y,Z,V)
# -> draw contour lines at the values specified in sequence *V*

like in

x, y = np.meshgrid(np.linspace(0, 1, 100), np.linspace(0, 1, 50))
z = x**4 - x**2 + np.sin(y)
contour(x, y, z, [-0.2, 0.0, 0.2, 0.4, 0.6, 0.8])

Kind regards,
Matthias

···

On Thursday 11 February 2010 21:58:15 Bruce Ford wrote:

In using the contour as in:

contour(X,Y,Z,N)

N is a number of automatically chosen levels.

I would like to contour based on data divisions.

For instance, perhaps I'd like to use a contour or color-fill
(contourf) every 2 units. I'm not seeing how to accomplish this. Any
points in the right direction would be appreciated.

Thanks!

Bruce

#3

Thanks for this. I didn't realize that N could be an array and
contour would know that these are the levels desired.

I found similar in an example, but not in the contour documentation.

Thanks so much!

Bruce

···

---------------------------------------
Bruce W. Ford
Clear Science, Inc.
bruce@...2905...
bruce.w.ford.ctr@...2906...
http://www.ClearScienceInc.com
Phone/Fax: 904-379-9704
8241 Parkridge Circle N.
Jacksonville, FL 32211
Skype: bruce.w.ford
Google Talk: fordbw@...287...

On Fri, Feb 12, 2010 at 7:29 AM, Matthias Michler <MatthiasMichler@...361...> wrote:

Hi Bruce,

why don't you use contour as in the following :wink:

contour(X,Y,Z,V)
# -> draw contour lines at the values specified in sequence *V*

like in

x, y = np.meshgrid(np.linspace(0, 1, 100), np.linspace(0, 1, 50))
z = x**4 - x**2 + np.sin(y)
contour(x, y, z, [-0.2, 0.0, 0.2, 0.4, 0.6, 0.8])

Kind regards,
Matthias

On Thursday 11 February 2010 21:58:15 Bruce Ford wrote:

In using the contour as in:

contour(X,Y,Z,N)

N is a number of automatically chosen levels.

I would like to contour based on data divisions.

For instance, perhaps I'd like to use a contour or color-fill
(contourf) every 2 units. I'm not seeing how to accomplish this. Any
points in the right direction would be appreciated.

Thanks!

Bruce

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#4

Thanks for this. I didn't realize that N could be an array and
contour would know that these are the levels desired.

I found similar in an example, but not in the contour documentation.

Just a remark: I use the help of IPython to investigate the doc-strings of
matplotlib-functions. The input "contour?" tells me
    ::
    
      contour(Z,V)
      contour(X,Y,Z,V)
    
    draw contour lines at the values specified in sequence *V*

Kind regards,
Matthias

···

On Friday 12 February 2010 15:11:17 Bruce Ford wrote:

Thanks so much!

Bruce

On Fri, Feb 12, 2010 at 7:29 AM, Matthias Michler > > <MatthiasMichler@...361...> wrote:
> Hi Bruce,
>
> why don't you use contour as in the following :wink:
>
> contour(X,Y,Z,V)
> # -> draw contour lines at the values specified in sequence *V*
>
> like in
>
> x, y = np.meshgrid(np.linspace(0, 1, 100), np.linspace(0, 1, 50))
> z = x**4 - x**2 + np.sin(y)
> contour(x, y, z, [-0.2, 0.0, 0.2, 0.4, 0.6, 0.8])
>
> Kind regards,
> Matthias
>
> On Thursday 11 February 2010 21:58:15 Bruce Ford wrote:
>> In using the contour as in:
>>
>> contour(X,Y,Z,N)
>>
>> N is a number of automatically chosen levels.
>>
>> I would like to contour based on data divisions.
>>
>> For instance, perhaps I'd like to use a contour or color-fill
>> (contourf) every 2 units. I'm not seeing how to accomplish this. Any
>> points in the right direction would be appreciated.
>>
>> Thanks!
>>
>> Bruce