Hi all,

with the simple code here below

$ ipython -pylab

In [1]: import numpy as np

In [2]: theta = np.arange(0., 2., 1./180.)*np.pi

In [3]: plt.polar(3*theta, theta/5)

I obtain the attached images with 0.98.5.3 and 0.99.{0.1rc1} (didn't

have time to test against SVN).

AFAIUI, the 0.98.5.3 should be the correct behavior, so in 0.99.x

there's a regression.

Regards,

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Sandro Tosi (aka morph, morpheus, matrixhasu)

My website: http://matrixhasu.altervista.org/

Me at Debian: http://wiki.debian.org/SandroTosi