 # plot

I want help on graph
I need to plot numbers one by one (lets say after interval of 5 sec) but
all in the same graph. How to do ?
My code is below

import time
import matplotlib.pyplot as plt
import numpy as np
from random import randint
i = 1
numbers = *5
while i < 5:
numbers[i] = randint(0,100)
plt.plot(np.arange(1,6),numbers, 'o')
i += 1
matplotlib.pyplot.draw()
time.sleep(5)
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Try using plt.pause instead of time.sleep. This may do what you want

import matplotlib.pyplot as plt
from random import randint

numbers = *5
# draw the initial points
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)
for i in range(5):
numbers[i] = randint(0,100)
# remove the previously plotted lines before drawing the new ones
oldlines.remove()
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)

···

On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:

I want help on graph
I need to plot numbers one by one (lets say after interval of 5 sec) but all in the same graph. How to do ?
My code is below

import time
import matplotlib.pyplot as plt
import numpy as np
from random import randint
i = 1
numbers = *5
while i < 5:
numbers[i] = randint(0,100)
plt.plot(np.arange(1,6),numbers, 'o')
i += 1
matplotlib.pyplot.draw()
time.sleep(5)
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It worked. However, I was looking for in one graph but here it's producing
n no of graphs. can we make it in the graph ?
partha

···

On Fri, 31 May 2019 at 21:10, Scott Lasley <selasley at icloud.com> wrote:

Try using plt.pause instead of time.sleep. This may do what you want

import matplotlib.pyplot as plt
from random import randint

numbers = *5
# draw the initial points
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)
for i in range(5):
numbers[i] = randint(0,100)
# remove the previously plotted lines before drawing the new ones
oldlines.remove()
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)

> On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:
>
> I want help on graph
> I need to plot numbers one by one (lets say after interval of 5 sec) but
all in the same graph. How to do ?
> My code is below
>
>
> import time
> import matplotlib.pyplot as plt
> import numpy as np
> from random import randint
> i = 1
> numbers = *5
> while i < 5:
> numbers[i] = randint(0,100)
> plt.plot(np.arange(1,6),numbers, 'o')
> i += 1
> matplotlib.pyplot.draw()
> time.sleep(5)
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users

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Are you making the plots in a jupyter notebook? The code worked for me in ipython and when saved as a file and run from the command line, but it does produce multiple plots in a jupyter notebook.

plt.pause does not seem to work in a notebook. The documentation for plt.pause says "This can be used for crude animation. For more complex animation, see matplotlib.animation." The snippet below is based on the matplotlib simple animation example (https://matplotlib.org/examples/animation/basic_example.html) It works in a jupyter notebook if you use the magic
%matplotlib notebook
or
%matplotlib nbagg
but it does not work in jupyter lab since those magics are not supported.

%matplotlib nbagg

import numpy as np
from matplotlib import pyplot as plt
from matplotlib.animation import FuncAnimation

def draw_pts(i):
y[i] = np.random.randint(10, 100)
pts.set_data(x, y)
ax.relim()
ax.autoscale_view(scaley=True)
return [pts]

def init_pts():
return []

x = np.arange(1, 6)
# set y to nan's so no points are drawn initially
y = np.full(5, np.nan)

fig, ax = plt.subplots()
ax.set(xlim=[0, 6])
pts = ax.plot(x, y, 'o')

anim = FuncAnimation(fig,
draw_pts,
frames=5,
init_func=init_pts,
interval=2000,
blit=True,
repeat=False)

Notes: If init_func is not set, draw_pts is called twice with i = 0, so I used a dummy init_pts function. ax.autoscale_view works in the jyputer notebook but the y axis does not update properly if the code is run in ipython on my mac. If repeat=True, draw_pts will be called forever with i ranging from 0 to frames - 1 repeatedly. interval sets the delay between updates in milliseconds.

hth,
Scott

···

On May 31, 2019, at 12:11 PM, Partha Sinha <pnsinha68 at gmail.com> wrote:

It worked. However, I was looking for in one graph but here it's producing n no of graphs. can we make it in the graph ?
partha

On Fri, 31 May 2019 at 21:10, Scott Lasley <selasley at icloud.com> wrote:
Try using plt.pause instead of time.sleep. This may do what you want

import matplotlib.pyplot as plt
from random import randint

numbers = *5
# draw the initial points
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)
for i in range(5):
numbers[i] = randint(0,100)
# remove the previously plotted lines before drawing the new ones
oldlines.remove()
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)

> On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:
>
> I want help on graph
> I need to plot numbers one by one (lets say after interval of 5 sec) but all in the same graph. How to do ?
> My code is below
>
>
> import time
> import matplotlib.pyplot as plt
> import numpy as np
> from random import randint
> i = 1
> numbers = *5
> while i < 5:
> numbers[i] = randint(0,100)
> plt.plot(np.arange(1,6),numbers, 'o')
> i += 1
> matplotlib.pyplot.draw()
> time.sleep(5)
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users