Hi Andrew,

if I understand correctly "set_clip_path" is what you want.

The usage was discussed in the following threads, where John Hunter also

proposed the example code added below.

http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg10155.html

http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg08779.html

The only example I found on the web and in the svn-examples about clip_path is

http://matplotlib.sourceforge.net/examples/pylab_examples/image_clip_path.html?highlight=clip_path

For developers: Could it be useful to include John's example in the online

screenshots / gallery or did I miss it?

best regards Matthias

"""

Clipping to arbitrary patches and paths

"""

import numpy as np

import matplotlib.pyplot as plt

import matplotlib.path as path

import matplotlib.patches as patches

fig = plt.figure()

ax = fig.add_subplot(111, frameon=False, xticks=[], yticks=[])

im = ax.imshow(np.random.rand(10,10))

patch = patches.Circle((300,300), radius=100)

im.set_clip_path(patch)

plt.show()

## ···

On Wednesday 15 April 2009 09:01:56 Andrew Kelly wrote:

Hello,I am relatively new to matplotlib but I get the basics. What I need

to do though is a slightly customized graph area. There are two plots on

the same graph - a parabola and a straight line (with a negative slope)

north east of the parabola. This graph has grid lines. Simple enough, but

now I want to remove the graph area to the right of the line. Think of a

dog-eared page in a book. Basically that top right triangle is gone.

Can I do this in MPL or do I need to do some post processing in PIL? Much

thanks for any help.

-Andrew