Hi List,
How can I make a plot have the same width as an image? The image (and
contour) have a fixed aspect ratio defined by the data. Now I'd like to
plot something under that image, with the same width.
I think this is trivial. I think I've done this in the past. But I
cannot find the code. Searching online and with experiments I've looked
into "sharex", and tried using "extent" and the bbox,
ax.transData.inverted(), etc. but I have not had any success, hence my
post here.
The following code demonstrates the problem. The 2nd axis is wider than
the first that contains the image.
Thanks,
-k.
fig = plt.figure(1)
fig.clf()
data = np.random.random((3,3))
xaxis = np.arange(0,3)
yaxis = np.arange(0,3)
ax = fig.add_subplot(211)
im = ax.imshow(data, interpolation='none')
c = ax.contour(xaxis, yaxis, data, colors='k')
ax2 = fig.add_subplot(212)
from matplotlib.pylab import *
fig = plt.figure(1)
fig.clf()
data = np.random.random((3,3))
xaxis = np.arange(0,3)
yaxis = np.arange(0,3)
ax1 = fig.add_subplot(211)
im = ax1.imshow(data, interpolation='none')
c = ax1.contour(xaxis, yaxis, data, colors='k')
···
#----------------
# draw ax1 first, so you can get proper position of ax1
fig.canvas.draw()
point_bl, point_tr = ax1.get_position().get_points() # ax1's bottom-left
and top-right
ax2 = fig.add_subplot(212)
space = 0.45 # space between ax2's bottom left and ax1's bottom left in
percentage
ax2.set_position([point_bl[0], point_bl[1]-space,
point_tr[0] - point_bl[0], point_tr[1] - point_bl[1]])
plt.show()
You can adjust that variable "space" as you need.
If someone has some more easy ways to do this, please let me know.
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Hi Zhangtao,
When I run that code I do not see the 2nd subplot. If I add “fig.canvas.draw()” to the bottom, it appears, but it is not the same width as the upper subplot.
···
On Tue, Nov 18, 2014 at 10:15 AM, zhangtao <tao.quiver@…287…> wrote:
from matplotlib.pylab import *
fig = plt.figure(1)
fig.clf()
data = np.random.random((3,3))
xaxis = np.arange(0,3)
yaxis = np.arange(0,3)
ax1 = fig.add_subplot(211)
im = ax1.imshow(data, interpolation=‘none’)
c = ax1.contour(xaxis, yaxis, data, colors=‘k’)
#----------------
draw ax1 first, so you can get proper position of ax1
fig.canvas.draw()
point_bl, point_tr = ax1.get_position().get_points() # ax1’s bottom-left
and top-right
ax2 = fig.add_subplot(212)
space = 0.45 # space between ax2’s bottom left and ax1’s bottom left in
percentage
ax2.set_position([point_bl[0], point_bl[1]-space,
point_tr[0] - point_bl[0], point_tr[1] - point_bl[1]])
plt.show()
You can adjust that variable “space” as you need.
If someone has some more easy ways to do this, please let me know.
–
View this message in context: http://matplotlib.1069221.n5.nabble.com/aligning-plot-width-with-imshow-contour-width-tp44408p44409.html
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I use matolotlib 1.3.1 on windows, the code works fine here.
<http://matplotlib.1069221.n5.nabble.com/file/n44444/figure_1.png>
what version of matolotlib are you using?
Or, set space to 0, see what happens.
···
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I'm using mpl 1.4.2.
I posted this question onto StackOverflow and got a nice reply/tutorial.
https://stackoverflow.com/questions/26985210/
Thanks,
-k.
