# [Question] Possible bug in plotting large NumPy array

Dear Matplotlib users,

I am P?ter Juh?sz and I started experimenting with this demo:
http://matplotlib.org/examples/pylab_examples/subplots_demo.html.

What I then tried to achieve is to let y be a NumPy array of 2 rows, the
first holding sin(x**2) values, the second holding something else (I set
cos(x**2)), and the make the same plots as in the original demo only by
using the first row of y. Unfortunately, I was quite surprised to see that
pyplot/matplotlib only succeeds with this plotting if scatter plots or
markers are used only, instead of the usual plotting with lines. On the
other hand, with some tricks in the NumPy array (some reshapes and slicing)
I was able to make pyplot/matplotlib work for both scatter plots and the
usual simple plots. This however possibly takes much more time, so for big
datasets does not seem feasible and anyway I do not see an obvious reason
why a dataset should only work with scatter plots but not the usual, simple
plots.

Please find attached my code below and I would appreciate any
help/explanation, or it is indeed a bug, then if it could be raised to the
developers' attention.

My original trial, working only with scatter plots (see for yourself! maybe
it's only my installation what is going wrong?):

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(1, 400)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2)))

print(y[:1].shape)

plt.close('all')

# Three subplots sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title('Sharing both axes')

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')

# Fine-tune figure; make subplots close to each other and hide x ticks for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title('Sharing x per column, y per row')

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')

ax4.plot(x, 2 * y[:1] ** 2 - 1, color='r') # This is not showing!

plt.show()

The working solution:

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(400, 1)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2))).reshape(400, 2)

print(y[:, 0].shape)

plt.close('all')

# Three subplots sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:, 0])

ax1.set_title('Sharing both axes')

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')

# Fine-tune figure; make subplots close to each other and hide x ticks for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')

ax1.plot(x, y[:, 0])

ax1.set_title('Sharing x per column, y per row')

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')

ax4.plot(x, 2 * y[:, 0] ** 2 - 1, color='r')

plt.show()

I did not modify anything else in the code respective to the original demo
than what I mentioned. I hope you will be able to help.

Kind regards,

P?ter

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The problem is the way you are slicing your data

by doing y[:1] you are creating a 1 by 400 array. When you try to plot that
you will get 400 individual line plots each with only one point. A line
plot with one point is invisible since there in no other points to draw the
lines between. You will not notice that with scatter since it defaults to
drawing a point for each data point. If you add a marker you can see whats
going on.
I.e. do
ax1.plot(x, y[:1], 'o')
in the first example and you will notice that the points color cycle as a
new plot is created.

If you really want to slice this way you have to ensure that your data is
along the first dimension. I.e. you can do `ax1.plot(x.transpose(),
y[:1].transpose())` which plots 400 by 1 arrays

Hope that helps
Jens

···

On Fri, 19 Aug 2016 at 11:10 <juhaszp95 at gmail.com> wrote:

Dear Matplotlib users,

I am P?ter Juh?sz and I started experimenting with this demo:
http://matplotlib.org/examples/pylab_examples/subplots_demo.html.

What I then tried to achieve is to let *y* be a NumPy array of 2 rows,
the first holding sin(x**2) values, the second holding something else (I
set cos(x**2)), and the make the same plots as in the original demo only by
using the first row of *y*. Unfortunately, I was quite surprised to see
that pyplot/matplotlib only succeeds with this plotting if *scatter plots*
or *markers* are used *only*, instead of the usual plotting with lines.
On the other hand, with some tricks in the NumPy array (some reshapes and
slicing) I was able to make pyplot/matplotlib work for both scatter plots
and the usual simple plots. This however possibly takes much more time, so
for big datasets does not seem feasible and anyway I do not see an obvious
reason why a dataset should only work with scatter plots but not the usual,
simple plots.

Please find attached my code below and I would appreciate any
help/explanation, or it is indeed a bug, then if it could be raised to the
developers? attention.

My original trial, working only with scatter plots (see for yourself!
maybe it?s only my installation what is going wrong?):

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(1, 400)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2)))

print(y[:1].shape)

plt.close(*'all'*)

# Three *subplots* sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title(*'Sharing both axes'*)

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color=*'r'*)

# Fine-tune figure; make *subplots* close to each other and hide x ticks
for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex=*'col'*, sharey=
*'row'*)

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title(*'Sharing x per column, y per row'*)

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color=*'r'*)

ax4.plot(x, 2 * y[:1] ** 2 - 1, color=*'r'*) # This is not showing!

plt.show()

The working solution:

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(400, 1)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2))).reshape(400, 2)

print(y[:, 0].shape)

plt.close(*'all'*)

# Three *subplots* sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:, 0])

ax1.set_title(*'Sharing both axes'*)

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)

# Fine-tune figure; make *subplots* close to each other and hide x ticks
for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex=*'col'*, sharey=
*'row'*)

ax1.plot(x, y[:, 0])

ax1.set_title(*'Sharing x per column, y per row'*)

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)

ax4.plot(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)

plt.show()

I did not modify anything else in the code respective to the original demo
than what I mentioned. I hope you will be able to help.

Kind regards,

P?ter
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users at python.org
Matplotlib-users Info Page

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Hi Jens,

Thanks very much! This indeed works. I thought PyPlot automatically detects if the data is along which axes, but fair, expecting it in a certain way is more consistent.

Many thanks for your help once again!

Best wishes,
P?ter

···

From: Jens Nielsen [mailto:jenshnielsen@gmail.com]
Sent: Friday, August 19, 2016 12:32 PM
To: juhaszp95 at gmail.com; matplotlib-users at python.org
Subject: Re: [Matplotlib-users] [Question] Possible bug in plotting large NumPy array

The problem is the way you are slicing your data

by doing y[:1] you are creating a 1 by 400 array. When you try to plot that you will get 400 individual line plots each with only one point. A line plot with one point is invisible since there in no other points to draw the lines between. You will not notice that with scatter since it defaults to drawing a point for each data point. If you add a marker you can see whats going on.

I.e. do

ax1.plot(x, y[:1], 'o')

in the first example and you will notice that the points color cycle as a new plot is created.

If you really want to slice this way you have to ensure that your data is along the first dimension. I.e. you can do `ax1.plot(x.transpose(), y[:1].transpose())` which plots 400 by 1 arrays

Hope that helps

Jens

On Fri, 19 Aug 2016 at 11:10 <juhaszp95 at gmail.com <mailto:juhaszp95 at gmail.com> > wrote:

Dear Matplotlib users,

I am P?ter Juh?sz and I started experimenting with this demo: http://matplotlib.org/examples/pylab_examples/subplots_demo.html.

What I then tried to achieve is to let y be a NumPy array of 2 rows, the first holding sin(x**2) values, the second holding something else (I set cos(x**2)), and the make the same plots as in the original demo only by using the first row of y. Unfortunately, I was quite surprised to see that pyplot/matplotlib only succeeds with this plotting if scatter plots or markers are used only, instead of the usual plotting with lines. On the other hand, with some tricks in the NumPy array (some reshapes and slicing) I was able to make pyplot/matplotlib work for both scatter plots and the usual simple plots. This however possibly takes much more time, so for big datasets does not seem feasible and anyway I do not see an obvious reason why a dataset should only work with scatter plots but not the usual, simple plots.

Please find attached my code below and I would appreciate any help/explanation, or it is indeed a bug, then if it could be raised to the developers? attention.

My original trial, working only with scatter plots (see for yourself! maybe it?s only my installation what is going wrong?):

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(1, 400)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2)))

print(y[:1].shape)

plt.close('all')

# Three subplots sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title('Sharing both axes')

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')

# Fine-tune figure; make subplots close to each other and hide x ticks for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')

ax1.plot(x, y[:1]) # This is not showing!

ax1.set_title('Sharing x per column, y per row')

ax2.scatter(x, y[:1])

ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')

ax4.plot(x, 2 * y[:1] ** 2 - 1, color='r') # This is not showing!

plt.show()

The working solution:

import matplotlib.pyplot as plt

import numpy as np

# Simple data to display in various forms

x = np.linspace(0, 2 * np.pi, 400).reshape(400, 1)

print(x.shape)

y = np.vstack((np.sin(x ** 2), np.cos(x ** 2))).reshape(400, 2)

print(y[:, 0].shape)

plt.close('all')

# Three subplots sharing both x/y axes

f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)

ax1.plot(x, y[:, 0])

ax1.set_title('Sharing both axes')

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')

# Fine-tune figure; make subplots close to each other and hide x ticks for

# all but bottom plot.

plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing

f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')

ax1.plot(x, y[:, 0])

ax1.set_title('Sharing x per column, y per row')

ax2.scatter(x, y[:, 0])

ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')

ax4.plot(x, 2 * y[:, 0] ** 2 - 1, color='r')

plt.show()

I did not modify anything else in the code respective to the original demo than what I mentioned. I hope you will be able to help.

Kind regards,

P?ter

_______________________________________________
Matplotlib-users mailing list
Matplotlib-users at python.org <mailto:Matplotlib-users at python.org>
https://mail.python.org/mailman/listinfo/matplotlib-users

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Hi:

I am trying to learn the basics of plotting in matplotlib. My immediate need is for displaying grayscale images with titles, axis labels & ticks and within-image annotations. Where can I get good tutorials/demos for such things?

Thanks.

Dipu

Dipankar ?Dipu? Ganguly
dipugee at gmail.com
Cell: 408-203-8814

···

On Aug 19, 2016, at 4:31 AM, <juhaszp95 at gmail.com> <juhaszp95 at gmail.com> wrote:

Hi Jens,

Thanks very much! This indeed works. I thought PyPlot automatically detects if the data is along which axes, but fair, expecting it in a certain way is more consistent.

Many thanks for your help once again!

Best wishes,
P?ter
? <>
From: Jens Nielsen [mailto:jenshnielsen at gmail.com <mailto:jenshnielsen at gmail.com>]
Sent: Friday, August 19, 2016 12:32 PM
To: juhaszp95 at gmail.com <mailto:juhaszp95 at gmail.com>; matplotlib-users at python.org <mailto:matplotlib-users at python.org>
Subject: Re: [Matplotlib-users] [Question] Possible bug in plotting large NumPy array

The problem is the way you are slicing your data

by doing y[:1] you are creating a 1 by 400 array. When you try to plot that you will get 400 individual line plots each with only one point. A line plot with one point is invisible since there in no other points to draw the lines between. You will not notice that with scatter since it defaults to drawing a point for each data point. If you add a marker you can see whats going on.
I.e. do
ax1.plot(x, y[:1], 'o')
in the first example and you will notice that the points color cycle as a new plot is created.

If you really want to slice this way you have to ensure that your data is along the first dimension. I.e. you can do `ax1.plot(x.transpose(), y[:1].transpose())` which plots 400 by 1 arrays

Hope that helps
Jens

On Fri, 19 Aug 2016 at 11:10 <juhaszp95 at gmail.com <mailto:juhaszp95 at gmail.com>> wrote:

Dear Matplotlib users,

I am P?ter Juh?sz and I started experimenting with this demo: http://matplotlib.org/examples/pylab_examples/subplots_demo.html.

What I then tried to achieve is to let y be a NumPy array of 2 rows, the first holding sin(x**2) values, the second holding something else (I set cos(x**2)), and the make the same plots as in the original demo only by using the first row of y. Unfortunately, I was quite surprised to see that pyplot/matplotlib only succeeds with this plotting if scatter plots or markers are used only, instead of the usual plotting with lines. On the other hand, with some tricks in the NumPy array (some reshapes and slicing) I was able to make pyplot/matplotlib work for both scatter plots and the usual simple plots. This however possibly takes much more time, so for big datasets does not seem feasible and anyway I do not see an obvious reason why a dataset should only work with scatter plots but not the usual, simple plots.

Please find attached my code below and I would appreciate any help/explanation, or it is indeed a bug, then if it could be raised to the developers? attention.

My original trial, working only with scatter plots (see for yourself! maybe it?s only my installation what is going wrong?):

import matplotlib.pyplot as plt
import numpy as np

# Simple data to display in various forms
x = np.linspace(0, 2 * np.pi, 400).reshape(1, 400)
print(x.shape)
y = np.vstack((np.sin(x ** 2), np.cos(x ** 2)))
print(y[:1].shape)

plt.close('all')

# Three subplots sharing both x/y axes
f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)
ax1.plot(x, y[:1]) # This is not showing!
ax1.set_title('Sharing both axes')
ax2.scatter(x, y[:1])
ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')
# Fine-tune figure; make subplots close to each other and hide x ticks for
# all but bottom plot.
plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing
f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')
ax1.plot(x, y[:1]) # This is not showing!
ax1.set_title('Sharing x per column, y per row')
ax2.scatter(x, y[:1])
ax3.scatter(x, 2 * y[:1] ** 2 - 1, color='r')
ax4.plot(x, 2 * y[:1] ** 2 - 1, color='r') # This is not showing!

plt.show()

The working solution:

import matplotlib.pyplot as plt
import numpy as np

# Simple data to display in various forms
x = np.linspace(0, 2 * np.pi, 400).reshape(400, 1)
print(x.shape)
y = np.vstack((np.sin(x ** 2), np.cos(x ** 2))).reshape(400, 2)
print(y[:, 0].shape)

plt.close('all')

# Three subplots sharing both x/y axes
f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)
ax1.plot(x, y[:, 0])
ax1.set_title('Sharing both axes')
ax2.scatter(x, y[:, 0])
ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')
# Fine-tune figure; make subplots close to each other and hide x ticks for
# all but bottom plot.
plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing
f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex='col', sharey='row')
ax1.plot(x, y[:, 0])
ax1.set_title('Sharing x per column, y per row')
ax2.scatter(x, y[:, 0])
ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color='r')
ax4.plot(x, 2 * y[:, 0] ** 2 - 1, color='r')

plt.show()

I did not modify anything else in the code respective to the original demo than what I mentioned. I hope you will be able to help.

Kind regards,
P?ter
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users at python.org <mailto:Matplotlib-users at python.org>
https://mail.python.org/mailman/listinfo/matplotlib-users_______________________________________________

Matplotlib-users mailing list
Matplotlib-users at python.org <mailto:Matplotlib-users at python.org>
Matplotlib-users Info Page

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Dipu,

http://matplotlib.org/ has both a gallery if images (click the image to see
the source code) and a broad, organized list of examples.

I'd start there.

···

On Fri, Aug 19, 2016 at 7:58 AM, Dipankar ?Dipu? Ganguly <dipugee at gmail.com> wrote:

Hi:

I am trying to learn the basics of plotting in matplotlib. My immediate
need is for displaying grayscale images with titles, axis labels & ticks
and within-image annotations. Where can I get good tutorials/demos for
such things?

Thanks.

Dipu

Dipankar ?Dipu? Ganguly
dipugee at gmail.com
Cell: 408-203-8814

On Aug 19, 2016, at 4:31 AM, <juhaszp95 at gmail.com> <juhaszp95 at gmail.com> > wrote:

Hi Jens,

Thanks very much! This indeed works. I thought PyPlot automatically
detects if the data is along which axes, but fair, expecting it in a
certain way is more consistent.

Many thanks for your help once again!

Best wishes,
P?ter

*From:* Jens Nielsen [mailto:jenshnielsen at gmail.com
<jenshnielsen at gmail.com>]
*Sent:* Friday, August 19, 2016 12:32 PM
*To:* juhaszp95 at gmail.com; matplotlib-users at python.org
*Subject:* Re: [Matplotlib-users] [Question] Possible bug in plotting
large NumPy array

The problem is the way you are slicing your data

by doing y[:1] you are creating a 1 by 400 array. When you try to plot
that you will get 400 individual line plots each with only one point. A
line plot with one point is invisible since there in no other points to
draw the lines between. You will not notice that with scatter since it
defaults to drawing a point for each data point. If you add a marker you
can see whats going on.
I.e. do
ax1.plot(x, y[:1], 'o')
in the first example and you will notice that the points color cycle as a
new plot is created.

If you really want to slice this way you have to ensure that your data is
along the first dimension. I.e. you can do `ax1.plot(x.transpose(),
y[:1].transpose())` which plots 400 by 1 arrays

Hope that helps
Jens

On Fri, 19 Aug 2016 at 11:10 <juhaszp95 at gmail.com> wrote:

Dear Matplotlib users,

I am P?ter Juh?sz and I started experimenting with this demo:
http://matplotlib.org/examples/pylab_examples/subplots_demo.html.

What I then tried to achieve is to let *y* be a NumPy array of 2 rows,
the first holding sin(x**2) values, the second holding something else (I
set cos(x**2)), and the make the same plots as in the original demo only by
using the first row of *y*. Unfortunately, I was quite surprised to see
that pyplot/matplotlib only succeeds with this plotting if *scatter plots*
or *markers* are used *only*, instead of the usual plotting with lines.
On the other hand, with some tricks in the NumPy array (some reshapes and
slicing) I was able to make pyplot/matplotlib work for both scatter plots
and the usual simple plots. This however possibly takes much more time, so
for big datasets does not seem feasible and anyway I do not see an obvious
reason why a dataset should only work with scatter plots but not the usual,
simple plots.

Please find attached my code below and I would appreciate any
help/explanation, or it is indeed a bug, then if it could be raised to the
developers? attention.

My original trial, working only with scatter plots (see for yourself!
maybe it?s only my installation what is going wrong?):

import matplotlib.pyplot as plt
import numpy as np

# Simple data to display in various forms
x = np.linspace(0, 2 * np.pi, 400).reshape(1, 400)
print(x.shape)
y = np.vstack((np.sin(x ** 2), np.cos(x ** 2)))
print(y[:1].shape)

plt.close(*'all'*)

# Three *subplots* sharing both x/y axes
f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)
ax1.plot(x, y[:1]) # This is not showing!
ax1.set_title(*'Sharing both axes'*)
ax2.scatter(x, y[:1])
ax3.scatter(x, 2 * y[:1] ** 2 - 1, color=*'r'*)
# Fine-tune figure; make *subplots* close to each other and hide x ticks
for
# all but bottom plot.
plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing
f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex=*'col'*, sharey=
*'row'*)
ax1.plot(x, y[:1]) # This is not showing!
ax1.set_title(*'Sharing x per column, y per row'*)
ax2.scatter(x, y[:1])
ax3.scatter(x, 2 * y[:1] ** 2 - 1, color=*'r'*)
ax4.plot(x, 2 * y[:1] ** 2 - 1, color=*'r'*) # This is not showing!

plt.show()

The working solution:

import matplotlib.pyplot as plt
import numpy as np

# Simple data to display in various forms
x = np.linspace(0, 2 * np.pi, 400).reshape(400, 1)
print(x.shape)
y = np.vstack((np.sin(x ** 2), np.cos(x ** 2))).reshape(400, 2)
print(y[:, 0].shape)

plt.close(*'all'*)

# Three *subplots* sharing both x/y axes
f, (ax1, ax2, ax3) = plt.subplots(3, sharex=True, sharey=True)
ax1.plot(x, y[:, 0])
ax1.set_title(*'Sharing both axes'*)
ax2.scatter(x, y[:, 0])
ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)
# Fine-tune figure; make *subplots* close to each other and hide x ticks
for
# all but bottom plot.
plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=False)

# row and column sharing
f, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2, sharex=*'col'*, sharey=
*'row'*)
ax1.plot(x, y[:, 0])
ax1.set_title(*'Sharing x per column, y per row'*)
ax2.scatter(x, y[:, 0])
ax3.scatter(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)
ax4.plot(x, 2 * y[:, 0] ** 2 - 1, color=*'r'*)

plt.show()

I did not modify anything else in the code respective to the original demo
than what I mentioned. I hope you will be able to help.

Kind regards,
P?ter
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