Thanks, this works well with the following minor changes.

import numpy as np

import matplotlib.pyplot as plt

x, y = np.mgrid[-10:10:50j, -10:10:50j]

f = x*np.sin(y) + y * np.sin(x) -4.0

plt.contour(x, y, f, (0,))

plt.show()

## ···

On Jan 28, 2009, at 8:26 AM, projetmbc@...748... wrote:

I'm looking a solution for ploting relation like f(x;y)=0.

I usually just contour the function over the region. E.g.,

>>> import numpy as np

>>> import matplotlib.pyplot as plt

>>> x, y = mgrid[-10:10:50j, -10:10:50j]

>>> f = x**3 * y - 3.0

>>> contour(x, y, f, (0,))The fourth argument to contour is a list of contours to plot, here

only zero.-Rob