Thanks, this works well with the following minor changes.
import numpy as np
import matplotlib.pyplot as plt
x, y = np.mgrid[-10:10:50j, -10:10:50j]
f = x*np.sin(y) + y * np.sin(x) -4.0
plt.contour(x, y, f, (0,))
plt.show()
···
On Jan 28, 2009, at 8:26 AM, projetmbc@...748... wrote:
I'm looking a solution for ploting relation like f(x;y)=0.
I usually just contour the function over the region. E.g.,
>>> import numpy as np
>>> import matplotlib.pyplot as plt
>>> x, y = mgrid[-10:10:50j, -10:10:50j]
>>> f = x**3 * y - 3.0
>>> contour(x, y, f, (0,))The fourth argument to contour is a list of contours to plot, here
only zero.-Rob