[I'm not sure if this is best in 'devel' or 'users']
I'm trying to compute PSDs using matplotlib.mlab.psd and came across the "PSD amplitudes" thread from last year:
http://sourceforge.net/mailarchive/message.php?msg_id=472101A6.9080206%40isla.hawaii.edu
Using the latest version of psd on svn trunk (rev 6429) that added support for pad_to, I can now compute the Matlab pwelch
example using matplotlib. This example is given in the Signal Processing Toolbox User's Guide:
http://www.mathworks.com/access/helpdesk/help/pdf_doc/signal/signal_tb.pdf
(look on pages 2-23 and 2-24). Note I do not have easy access to Matlab itself, so I'm just using this published example.
The Matlab code is as follows:
randn('state',1)
fs = 1000; % Sampling frequency
t = (0:0.3*fs)./fs; % 301 samples
A = [2 8]; % Sinusoid amplitudes (row vector)
f = [150;140]; % Sinusoid frequencies (column vector)
xn = A*sin(2*pi*f*t) + 5*randn(size(t));
Hs = spectrum.welch('rectangular',150,50);
psd(Hs,xn,'Fs',fs,'NFFT',512);
This produces a fairly noisy signal from -20 to -10 dB, with a strong peak of ~6 dB at 150 Hz (see the plot on page 2-24).
While my equivalent (?) python code is:
from scipy import *
from mlabsvn import psd # This is a local copy of svn revision 6429 of matplotlib.mlab
from pylab import *
fs=1000
t=linspace(0,0.3,0.3*fs+1)
A=[2,8]
f=[150,140]
xn=A[0]*sin(2*pi*f[0]*t) + A[1]*sin(2*pi*f[1]*t) + 5*randn(len(t))
Pxx,freqs = psd(xn,Fs=fs,NFFT=150,noverlap=75,pad_to=512)
figure()
plot(freqs, 10*log10(Pxx) )
show()
However, this produces a peak of over 30 dB at 150 Hz. Unless there is a mistake in my code above, there seems to be a
significant difference between the matplotlib and matlab implementations.
I noticed that the values 10*log10(Pxx/len(xn)) produces results that match much better. Without looking more closely at the
code for psd and reviewing Bendat and Piersol I cannot be sure that this is the correct fix.
Does anyone else have any insight? When is the next release planned, and how likely is a fix?
Thanks,
Matt
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