loop through x and y axes

#1

Hi all,

Please consider this code:

fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=[14,4])

for ax in (ax1, ax2):
    ax.set_xlabel(labels[0])
    ax.set_ylabel(labels[1])

This could be simplified if I could just loop though the x and y axes of each subplot, something like:

for index, ax in enumerate((ax1, ax2)):
    ax.set_label[index](labels[index])

Is there some way of achieving this in Matplotlib? From what I found, it seems one can only refer to the axes using x and y, and so I don't know how to loop over both of them.

Thank you,
Andrei

#2

It sounds like you want to use the ``set_label_text`` method of the
``Axis`` instances directly? Perhaps something like:

import matplotlib.pyplot as plt

labels = ['xlabel', 'ylabel']

fig, axes = plt.subplots(ncols=2)
for ax in axes:
    for axis, label in zip([ax.xaxis, ax.yaxis], labels):
        axis.set(label_text=label)

fig.tight_layout()
plt.show()

However, that's not really much cleaner than doing:

import matplotlib.pyplot as plt

fig, axes = plt.subplots(ncols=2)
for ax in axes:
    ax.set(xlabel='xlabel', ylabel='ylabel')

fig.tight_layout()
plt.show()

However, I might be misunderstanding your question entirely... Hope that
helps a bit, anyway.
-Joe

···

On Fri, Oct 27, 2017 at 6:17 AM, Andrei Berceanu <berceanu at runbox.com> wrote:

Hi all,

Please consider this code:

fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=[14,4])

for ax in (ax1, ax2):
    ax.set_xlabel(labels[0])
    ax.set_ylabel(labels[1])

This could be simplified if I could just loop though the x and y axes of
each subplot, something like:

for index, ax in enumerate((ax1, ax2)):
    ax.set_label[index](labels[index])

Is there some way of achieving this in Matplotlib? From what I found, it
seems one can only refer to the axes using x and y, and so I don't know how
to loop over both of them.

Thank you,
Andrei
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https://mail.python.org/mailman/listinfo/matplotlib-users

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#3

How about, as recently pointed out by @anntzer on github:

fig, axs = plt.subplots(1, 2, figsize=[14, 4])
plt.setp(axs, ?xlabel?, labels[0], ?ylabel?, labels[1])

or, suppose you don?t want to repeat labels except on outer

fig, axs = plt.subplots(3, 3, figsize=[14, 4])
plt.setp(axs[-1,:], ?xlabel?, labels[0])
plt.setp(axs[0,:], ?ylabel?, labels[1])

Cheers, Jody

···

On 27 Oct 2017, at 4:17 AM, Andrei Berceanu <berceanu at runbox.com> wrote:

Hi all,

Please consider this code:

fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=[14,4])

for ax in (ax1, ax2):
   ax.set_xlabel(labels[0])
   ax.set_ylabel(labels[1])

This could be simplified if I could just loop though the x and y axes of each subplot, something like:

for index, ax in enumerate((ax1, ax2)):
   ax.set_label[index](labels[index])

Is there some way of achieving this in Matplotlib? From what I found, it seems one can only refer to the axes using x and y, and so I don't know how to loop over both of them.

Thank you,
Andrei
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users at python.org
https://mail.python.org/mailman/listinfo/matplotlib-users

--
Jody Klymak
http://web.uvic.ca/~jklymak/