darkside <in.the.darkside@...287...> writes:
x = np.fromstring(b,sep='')
That should be sep=' ' (a space) to make it read ASCII representations
of numbers. Otherwise it will interpret the string as binary, and if the
string length happens to be a multiple of 8, you get garbage data,
otherwise it raises the following exception:
ValueError: string size must be a multiple of element size
--
Jouni K. Sepp�nen
Thank your, but:
If the initial list is:
a
’ 0.000000000E+00 1.806088833E-02-4.959341557E+07 0.000000000E+00 0.000000000E+00\n’
y = np.fromstring(a2,sep=’ ')
y
array([ 0.00000000e+00, 1.80608883e-02, -4.95934156e+07,
0.00000000e+00, 0.00000000e+00])
It works perfectly.
But if the initial list is like:
b
‘-2.754367381E-182.028474614E-02 6.959906258E+10 -1.390014546E-01 0.000000000E+00\n 7.484873918E-06 0.000000000E+00 0.000000000E+00 5.132910511E-03 9.159690889E-03\n 5.247460000E-03 -3.938080000E-03 -4.047670000E-03 0.000000000E+00 0.000000000E+00\n\n’
np.fromstring(b,sep=’ ')
array([ 0.])
np.fromstring(b,sep=’ ')
array([ 8.56506822e-072, 2.92021791e-033, 2.25187638e+006, …,
6.99021630e-077, 1.39804329e-076, 2.66133772e-260])
It doesn’t work in anyway.
Maybe because of the \n? Do I have to put them off before trying fromstring?
2009/4/22 Jouni K. Seppänen <jks@…397…>
darkside <in.the.darkside@…287…> writes:
x = np.fromstring(b,sep=‘’)
That should be sep=’ ’ (a space) to make it read ASCII representations
of numbers. Otherwise it will interpret the string as binary, and if the
string length happens to be a multiple of 8, you get garbage data,
otherwise it raises the following exception:
ValueError: string size must be a multiple of element size
–
Jouni K. Seppänen
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darkside wrote:
Maybe because of the \n? Do I have to put them off before trying fromstring?
yes == fromstring/fromfile doesn't deal with mixing \n and space (or any other sep char), which is too bad, because this is a common use.
They could use some work in general.
but if you do a: s = s.replace('\n'," ") first, it should be fine.
-Chris
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