eliminating end labels on axes

James Boyle <boyle5@...99...> writes:

I have not been able to figure out how to just make the first and
last ytick labels vanish. [...]
I thought that the following might work but this just makes all the
labels disappear - my understanding is incomplete.
    ytl = a.get_yticklabels()
    ytl[0]._visible = False
    ytl[-1]._text = False

It is usually a bad idea to manipulate directly anything starting with
an underscore -- that's a Pythonic way of indicating a "private"
variable. The set_visible() method should work here:

ytl = a.get_yticklabels()
ytl[0].set_visible(False)

···

--
Jouni K. Sepp�nen
http://www.iki.fi/jks

I think I was the one who asked a similar question a while back. Here
is a link to John's response:
http://article.gmane.org/gmane.comp.python.matplotlib.general/5465

I followed his advice and created my own formatter:

from matplotlib.ticker import LogFormatterMathtext

class MyFormatter(LogFormatterMathtext):
   def __call__(self, x, pos=None):
       if pos==0: return '' # pos=0 is the first tick
       else: return LogFormatterMathtext.__call__(self, x, pos)

ax.xaxis.set_major_formatter(MyFormatter())

···

On 9/14/07, Jouni K. Seppänen <jks@...397...> wrote:

James Boyle <boyle5@...99...> writes:

> I have not been able to figure out how to just make the first and
> last ytick labels vanish. [...]
> I thought that the following might work but this just makes all the
> labels disappear - my understanding is incomplete.
> ytl = a.get_yticklabels()
> ytl[0]._visible = False
> ytl[-1]._text = False

It is usually a bad idea to manipulate directly anything starting with
an underscore -- that's a Pythonic way of indicating a "private"
variable. The set_visible() method should work here:

ytl = a.get_yticklabels()
ytl[0].set_visible(False)

--
Jouni K. Seppänen
http://www.iki.fi/jks

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