Ah, I was a little confused by what you wrote John (I though I had to
access contour through the axes object and the meaning of R, F, dR was
a little unclear..) however using the 'levels' keyword now works. i.e.
plt.contour(x, y, z, levels=[0])
Incidentally, this keyword (levels) is not documented at
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.contour
and in fact the documentation implies that contour(kx, ky, z, [0])
should work when it does not.
Perhaps the docs could be updated to reflect this?
Brendan
···
On Tue, Nov 3, 2009 at 2:19 PM, Brendan Arnold <brendanarnold@...287...> wrote:
Hi again,
Thanks for the responses, however neither work, the error still
persists. Here are more details...Traceback (most recent call last):
File "C:\Program Files\Python\2.5\lib\lib-tk\Tkinter.py", line 1403,
in __call__
return self.func(*args)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_tkagg.py",
line 212, in resize
self.show()
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_tkagg.py",
line 215, in draw
FigureCanvasAgg.draw(self)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_agg.py",
line 314, in draw
self.figure.draw(self.renderer)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\artist.py", line 46, in
draw_wrapper
draw(artist, renderer, *kl)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\figure.py", line 773, in
draw
for a in self.axes: a.draw(renderer)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\artist.py", line 46, in
draw_wrapper
draw(artist, renderer, *kl)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\axes.py", line 1735, in
draw
a.draw(renderer)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\text.py", line 515, in
draw
bbox, info = self._get_layout(renderer)
File "C:\Program
Files\Python\2.5\lib\site-packages\matplotlib\text.py", line 257, in
_get_layout
if key in self.cached: return self.cached[key]
TypeError: unhashable type: 'numpy.ndarray'matplotlib.__version__
'0.99.1'
numpy.__version__
'1.3.0'
Python version 2.5
the code in full is as follows,
import matplotlib
import numpy as np
import matplotlib.cm as cm
import matplotlib.mlab as mlab
import matplotlib.pyplot as plt# Set some model parameters
model_points = 10000
t0 = 0.38
t1 = 0.32*t0
t2 = 0.5*t1def energy(kx, ky):
'''Energy function, evetually this will be provided by raw data
from WIEN2k'''
return -2*t0*(np.cos(kx)+np.cos(ky)) \
+ 4*t1*np.cos(kx)*np.cos(ky) \
- 2*t2*(np.cos(2*kx)+np.cos(2*ky))def shift_energy_up(energy_val, dE):
'''Shifts the energy according to a gap'''
return energy_val + np.sqrt(energy_val**2 + dE**2)def shift_energy_dn(energy_val, dE):
'''Shifts the energy down according to an energy'''
return energy_val - np.sqrt(energy_val**2 + dE**2)kx = np.arange(0, 2*np.pi, 2*np.pi/np.sqrt(model_points))
ky = np.arange(0, 2*np.pi, 2*np.pi/np.sqrt(model_points))
mgx, mgy = np.meshgrid(kx, ky)
z = energy(mgx, mgy)# Set the ticks to go outwards
matplotlib.rcParams['xtick.direction'] = 'out'
matplotlib.rcParams['ytick.direction'] = 'out'plt.figure()
CS = plt.contour(kx, ky, z, [0, 0])
plt.clabel(CS, inline=1, fontsize=10)
plt.title('Simplest default with labels')
plt.show()kind regards,
Brendan
On Mon, Nov 2, 2009 at 9:33 PM, Pierre de Buyl <pdebuyl@...2144...> wrote:
From memory, you just need to make a length one list
contour(z, [i])
Pierre
Le 2 nov. 09 à 22:19, Brendan Arnold a écrit :
Hi there,
I can draw a single contour line in MATLAB using
contour(z, [i i])
however,
contour(z, [i, i])
using matplotlib gives an error. In fact any plot that plots a single
line (i.e. contour(z, 1)) also gives an error as follows,TypeError: unhashable type: 'numpy.ndarray'
How do I draw a single contour line using matplotlib?
regards,
Brendan
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