 # axes_grid divider with room for axis

hi, i'd like to use the divider stuff in axes_grid to plot a figure
with 2 axes, with xticks on the bottom axis.
in the script pasted below, if i use 0.07 as the min for the y-axis,
then it chops off the top of the plot. if i use 0 as the min, then
it doesn't chop of the top, but it doesnt show the x-axis
ticks/labels. how can i have the divider account for the room needed
for the
labels and ticks?

i've also tried:

hori = [Size.AxesX(axes)]
vert = [Size.Scaled(0.3), Size.Scaled(0.7)]
d = Divider(f, rect, hori, vert)

with same problem.
thanks,
-brent

···

===========================================

import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid import make_axes_locatable
import numpy as np
plt.close()

f = plt.figure()
rect = (0, 0.07, 1, 1)
#rect = (0, 0, 1, 1)

divider = make_axes_locatable(ax)

axes = [ax, ax2]

for ax in axes:
ax.plot(np.sin(np.linspace(0, 10, 1600)))
ax.set_xlim(0, 1600)
ax.set_ylim(-1, 1)
axes.set_xticks([])

plt.show()

Doing this automatically is not straight forward. So you need to
manually adjust the area occupied by the axes.
Note that rect is [left, bottom, width, height] in normalized figure
coordinate. Try something like rect=[0., 0.1, 1., 0.8], or simply use
subplot.

Regards,

-JJ

···

On Mon, Nov 9, 2009 at 6:03 PM, Brent Pedersen <bpederse@...287...> wrote:

how can i have the divider account for the room needed
for the
labels and ticks?

how can i have the divider account for the room needed
for the
labels and ticks?

Doing this automatically is not straight forward. So you need to
manually adjust the area occupied by the axes.
Note that rect is [left, bottom, width, height] in normalized figure
coordinate. Try something like rect=[0., 0.1, 1., 0.8], or simply use
subplot.

that does it. thanks, i forgot it was height, not ymax.
-brent

···

On Mon, Nov 9, 2009 at 3:18 PM, Jae-Joon Lee <lee.j.joon@...287...> wrote:

On Mon, Nov 9, 2009 at 6:03 PM, Brent Pedersen <bpederse@...287...> wrote:

Regards,

-JJ