Sterling,
I have version 1.2.0. I read the legend guide. Which thing should be
possible? If you mean giving the points as a tuple, here's some simple
test code:
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(1,1,1)
p1 = ax.scatter([0.1],[0.5],c='r',marker='s')
p2 = ax.scatter([0.3],[0.2],c='b',marker='o')
l = ax.legend((p1,p2),['points'],scatterpoints=2)
plt.show()
I get a legend with only red squares. What I want is a legend line with
a red square and a blue circle. I can get points with different colors
if I do:
p1 = ax.scatter([0.1,0.3],[0.5,0.2],c=('r','b'),marker='s')
l = ax.legend(['points'],scatterpoints=2)
(though as far as I can tell, you can't have a sequence of marker
types).
Jon
···
On Wed, 2013-01-23 at 09:57 -0800, Sterling Smith wrote:
Jon,
What version of matplotlib do you have? According to
http://matplotlib.org/users/legend_guide.html
what you say should be possible in 1.2.0.-Sterling
On Jan 23, 2013, at 9:35AM, Jonathan Slavin wrote:
> Hi,
>
> I'm wondering if there is some straightforward way to combine two
> PathCollection objects to create a new PathCollection object. My goal
> is to include two points that use different axes (one twin'ed to the
> other) into a single legend item (different point types, same label).
> Each call to scatter creates a new PathCollection object. If I could
> just combine two (or more) PathCollection objects -- either extending
> them or concatenating or whatever -- then I could give that to legend
> and it would work correctly. But it's not clear to me how I can do
> that. I tried providing the two objects as a tuple to legend, but it
> doesn't work (only point characteristics of one of them is used).
>
> Really, I think this should be easier -- both the combining of such
> objects (which after all, are collections) and providing legend with
> simple arguments to produce what you want. As far as I can tell I can't
> just tell leged directly the symbol type(s) and colors of point(s) per
> each label. Though in general the automatic method whereby you provide
> the object to the legend is nice and easy, a more crude and direct way
> would be a good option for special cases.
>
> Jon
> --
> ______________________________________________________________
> Jonathan D. Slavin Harvard-Smithsonian CfA
> jslavin@...1081... 60 Garden Street, MS 83
> phone: (617) 496-7981 Cambridge, MA 02138-1516
> cell: (781) 363-0035 USA
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--
______________________________________________________________
Jonathan D. Slavin Harvard-Smithsonian CfA
jslavin@...1081... 60 Garden Street, MS 83
phone: (617) 496-7981 Cambridge, MA 02138-1516
cell: (781) 363-0035 USA
______________________________________________________________